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Thread: figuring corner radius

  1. #1

    figuring corner radius

    corner radius.jpgis there a way to figure what numbers to put in the corner radius boxs to get them to come out a certain length?
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  2. #2
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    draw it 8 inches on a 22.5% angle

  3. #3
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    A*A + B*B = C*C since a and b are equal 2 ( A*A) = C*C you have the C actual the length so A = C*C /2 sqr rt


    Give us a number and see if it works


    so if you need a 8" length.. (8 x8) /2 = 32 the sqrt = 5.656854 that is the number you enter in corel bevel radius.





    Wow Me don't like math.

    Draw a 8 x 8" box in corel.... rotate 45* and reduce the box to the number you want 8" now rotate it back to 0* and read the measurements......much easier.. 5.657


    .
    Last edited by Mark Sipes; 08-20-2015 at 7:32 PM.
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  4. #4
    .7071 x Length across that leg (8" in this case) = length
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  5. #5
    yikes guys there has to be an easier way. corel will do radius, but I need to know what number to enter into the boxes. If I enter 8.25 looking for 8.25" lines its not right th lines are way to long,corner radius.jpgthere about 11 inches long.
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  6. #6
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    Bert,

    Are you trying to make octagon with 8" each side?

    If so, you can get this in corel by drawing square of 19.375 than go to Fillet/scallop/chamfer docker and enter 5.625" in Chamfer and it will generate you 8" sides
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  7. #7
    No I'm trying to get 8.25 on two sides my sq is 21.25

    Quote Originally Posted by Tony Lenkic View Post
    Bert,

    Are you trying to make octagon with 8" each side?

    If so, you can get this in corel by drawing square of 19.375 than go to Fillet/scallop/chamfer docker and enter 5.625" in Chamfer and it will generate you 8" sides
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  8. #8
    I think this is it Scott. if I multiply .7071 x the length I want and enter that number in the radius boxes I thunk it come out right. Thank you.? how did you come up with .7071???

    Quote Originally Posted by Scott Shepherd View Post
    .7071 x Length across that leg (8" in this case) = length
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  9. #9
    Bert

    This may be the hard way but make your square and convert it to curves. Make two squares 8.25" and rotate them 45 degrees. Position them right and top aligned and left and top aligned. Make a node on each side where the chamfer meets the square. then delete the corner node.
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  10. #10
    Like others said, you can enter 5.656854 (= .7071*8) in that dialog box to generate an 8" bevel. Since the bevel is at 45 degrees, the horizontal distance (A) from start to end of the bevel is the same as the vertical distance (B), and you want the bevel (C, the side you are creating on the 45 degree slope) to be 8", then it is as Mark explained, you use A squared plus B squared equals C squared. And A equals C so that reduces to 2 A squared equals C squared, or C = A times the square root of 2. And Scott rewrote that as .7071 * 8. QED
    Last edited by Glen Monaghan; 08-20-2015 at 8:57 PM.

  11. #11
    Quote Originally Posted by Mike Null View Post
    This may be the hard way but [...]
    Yes... ;^)

  12. #12
    I'm not exactly sure what your after, but--

    if you know the radius and you want the diagonal measurement (as shown in your diagram), multiply it by 141.4%...

    Conversely, if you know the diagonal measurement and want to know the radius, multiply by 70.7%...
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  13. #13
    Quote Originally Posted by Bert Kemp View Post
    I think this is it Scott. if I multiply .7071 x the length I want and enter that number in the radius boxes I thunk it come out right. Thank you.? how did you come up with .7071???
    Bert, .7071 is the Cosine value of 45 degrees. Cosine(45 degrees)= (Adjacent side)/(hypotenuse)

    .7071= X/8.000
    X= .7071*8.000
    X=5.565 (doing this from memory, so that number might not be exactly right)
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  14. #14
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    So the final answer is 5.834 produces a diagonal of 8.25"


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  15. #15
    Thanks guys I think Scott's method is the easiest as I have the number to work with,I don't understand all the other math, basic algebra was 45 years ago long forgotten, hated math.LOL.
    I'm going to assume this number only works as long as I'm using a 45° angle
    Last edited by Bert Kemp; 08-21-2015 at 7:48 AM.
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