OK Time to get serious. Just how does the Phil Thein Baffle work? To know how it works you need a bit of info on how a cyclone works and I will explain that below later on.
The Thein Baffle is just that, a baffle. The dust stream enters the container through an elbow directing the stream into a somewhat cyclonic action in the upper chamber. Centrifigal force pulls the particles to the outside of the spinning stream where they settle down to the lower chamber. There is a fair amount of turbulance introduced into the container from the elbow to the stream comming into the container and the Thien Baffle smoothes that turbulance out and prevents it from stirring up the entire contents of the container. You may think that the 90 degree elbow would direct the incomming stream 90 degrees, and you would only be partly correct. A good part of the stream will be a lot less than 90 degrees because the stream will take the path of least resistance. It is this off angle stream that keeps the solids stirred up a non baffled container instead of setteling down. Phil, have you tried the seperator with a smaller outside opening and a center opening somewhat like the cyclone has? The youtube vid is very impressive for what it is doing, and I think a good part of that is how air is introduced into the chamber. Side inlet will have less turbulance to start with, and not have the back of the elbow to run into.
And now for how a cyclone works. Seriously, look up cyclone seperator on wikipedia.
Steady state
As the cyclone is essentially a two phase particle-fluid system, fluid mechanics and particle transport equations can be used to describe the behaviour of a cyclone. The air in a cyclone is initially introduced tangentially into the cyclone with an inlet velocity
Vin. Assuming that the particle is spherical, a simple analysis to calculate critical separation particle sizes can be established.
Given that the fluid velocity is moving in a spiral the gas velocity can be broken into two component velocities: a tangential component,
Vt, and a radial velocity component
Vr. Assuming
Stokes' law, the drag force on any particle in this inlet stream is therefore given by the following equation:
Fd = 6πrpμVr. If one considers an isolated particle circling in the upper cylindrical component of the cyclone at a rotational radius of
r from the cyclone's central axis, the particle is therefore subjected to
centrifugal,
drag and
buoyant forces. The centrifugal component is given by:
The buoyant force component is obtained by the difference between the particle and fluid densities,
ρp and
ρf respectively:
The force balance can be created by summing the forces together
This rate is controlled by the diameter of the particle's orbit around the central axis of the cyclone. A particle in the cyclonic flow will move towards either the wall of the cyclone, or the central axis of the cyclone until the drag, buoyant and centrifugal forces are balanced. Assuming that the system has reached steady state, the particles will assume a characteristic radius dependent upon the force balance. Heavier, denser particles will assume a solid flow at some larger radius than light particles. The steady state balance assumes that for all particles, the forces are equated, hence:
Fd + Fc + Fb = 0 Which expands to:
This can be expressed by rearranging the above in terms of the particle radius. The particle radius as a function of cyclonic radius, fluid density and fluid tangential and rotational velocities can then be found to be:
Experimentally it is found that the velocity component of rotational flow is proportional to
r2[2], therefore:
This means that the established feed velocity controls the vortex rate inside the cyclone, and the velocity at an arbitrary radius is therefore:
Subsequently, given a value for
Vt, possibly based upon the injection angle, and a cutoff radius, a characteristic particle filtering radius can be estimated, above which particles will be removed from the gas stream.