Need an electrical engineer

[Gary Chester]

Sounds like you've got your answer, but here's another way to look at it...

Let say your amp is putting out 8 volts at "whatever" frequency into an 8 ohm load, that's 8 watts of power at the load (1 amp x 8 volts).

Now let's add that cap in series with the load and inject a 200hz sine wave, let's pick a cap value that happens to have an impedance of 72 ohms at 200hz.

The amp is still putting out 8 volts, but the load it sees is 80 ohms (8 ohms + 72 ohms). That gives a current of .1 amps, that means the amp is only putting out .8 watts (.1amp x 8 volts).

So your amp is not "cranking out the power at low frequencies", but it is "cranking out the voltage" at those frequency's.

Hope that helps...

[Phil Thien]

Sounds like you've got your answer, but here's another way to look at it...

Let say your amp is putting out 8 volts at "whatever" frequency into an 8 ohm load, that's 8 watts of power at the load (1 amp x 8 volts).

Now let's add that cap in series with the load and inject a 200hz sine wave, let's pick a cap value that happens to have an impedance of 72 ohms at 200hz.

The amp is still putting out 8 volts, but the load it sees is 80 ohms (8 ohms + 72 ohms). That gives a current of .1 amps, that means the amp is only putting out .8 watts (.1amp x 8 volts).

So your amp is not "cranking out the power at low frequencies", but it is "cranking out the voltage" at those frequency's.

Hope that helps...

Yep, good clarification, thank you.